3.665 \(\int \cos ^3(c+d x) \cot ^4(c+d x) (a+a \sin (c+d x)) \, dx\)

Optimal. Leaf size=118 \[ -\frac {a \sin ^4(c+d x)}{4 d}-\frac {a \sin ^3(c+d x)}{3 d}+\frac {3 a \sin ^2(c+d x)}{2 d}+\frac {3 a \sin (c+d x)}{d}-\frac {a \csc ^3(c+d x)}{3 d}-\frac {a \csc ^2(c+d x)}{2 d}+\frac {3 a \csc (c+d x)}{d}-\frac {3 a \log (\sin (c+d x))}{d} \]

[Out]

3*a*csc(d*x+c)/d-1/2*a*csc(d*x+c)^2/d-1/3*a*csc(d*x+c)^3/d-3*a*ln(sin(d*x+c))/d+3*a*sin(d*x+c)/d+3/2*a*sin(d*x
+c)^2/d-1/3*a*sin(d*x+c)^3/d-1/4*a*sin(d*x+c)^4/d

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Rubi [A]  time = 0.09, antiderivative size = 118, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2836, 12, 88} \[ -\frac {a \sin ^4(c+d x)}{4 d}-\frac {a \sin ^3(c+d x)}{3 d}+\frac {3 a \sin ^2(c+d x)}{2 d}+\frac {3 a \sin (c+d x)}{d}-\frac {a \csc ^3(c+d x)}{3 d}-\frac {a \csc ^2(c+d x)}{2 d}+\frac {3 a \csc (c+d x)}{d}-\frac {3 a \log (\sin (c+d x))}{d} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^3*Cot[c + d*x]^4*(a + a*Sin[c + d*x]),x]

[Out]

(3*a*Csc[c + d*x])/d - (a*Csc[c + d*x]^2)/(2*d) - (a*Csc[c + d*x]^3)/(3*d) - (3*a*Log[Sin[c + d*x]])/d + (3*a*
Sin[c + d*x])/d + (3*a*Sin[c + d*x]^2)/(2*d) - (a*Sin[c + d*x]^3)/(3*d) - (a*Sin[c + d*x]^4)/(4*d)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 2836

Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)
*(x_)])^(n_.), x_Symbol] :> Dist[1/(b^p*f), Subst[Int[(a + x)^(m + (p - 1)/2)*(a - x)^((p - 1)/2)*(c + (d*x)/b
)^n, x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, c, d, m, n}, x] && IntegerQ[(p - 1)/2] && EqQ[a^2 - b^2,
0]

Rubi steps

\begin {align*} \int \cos ^3(c+d x) \cot ^4(c+d x) (a+a \sin (c+d x)) \, dx &=\frac {\operatorname {Subst}\left (\int \frac {a^4 (a-x)^3 (a+x)^4}{x^4} \, dx,x,a \sin (c+d x)\right )}{a^7 d}\\ &=\frac {\operatorname {Subst}\left (\int \frac {(a-x)^3 (a+x)^4}{x^4} \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {\operatorname {Subst}\left (\int \left (3 a^3+\frac {a^7}{x^4}+\frac {a^6}{x^3}-\frac {3 a^5}{x^2}-\frac {3 a^4}{x}+3 a^2 x-a x^2-x^3\right ) \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {3 a \csc (c+d x)}{d}-\frac {a \csc ^2(c+d x)}{2 d}-\frac {a \csc ^3(c+d x)}{3 d}-\frac {3 a \log (\sin (c+d x))}{d}+\frac {3 a \sin (c+d x)}{d}+\frac {3 a \sin ^2(c+d x)}{2 d}-\frac {a \sin ^3(c+d x)}{3 d}-\frac {a \sin ^4(c+d x)}{4 d}\\ \end {align*}

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Mathematica [A]  time = 0.21, size = 103, normalized size = 0.87 \[ -\frac {a \sin ^3(c+d x)}{3 d}+\frac {3 a \sin (c+d x)}{d}-\frac {a \csc ^3(c+d x)}{3 d}+\frac {3 a \csc (c+d x)}{d}-\frac {a \left (\sin ^4(c+d x)-6 \sin ^2(c+d x)+2 \csc ^2(c+d x)+12 \log (\sin (c+d x))\right )}{4 d} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^3*Cot[c + d*x]^4*(a + a*Sin[c + d*x]),x]

[Out]

(3*a*Csc[c + d*x])/d - (a*Csc[c + d*x]^3)/(3*d) + (3*a*Sin[c + d*x])/d - (a*Sin[c + d*x]^3)/(3*d) - (a*(2*Csc[
c + d*x]^2 + 12*Log[Sin[c + d*x]] - 6*Sin[c + d*x]^2 + Sin[c + d*x]^4))/(4*d)

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fricas [A]  time = 0.68, size = 139, normalized size = 1.18 \[ -\frac {32 \, a \cos \left (d x + c\right )^{6} + 192 \, a \cos \left (d x + c\right )^{4} - 768 \, a \cos \left (d x + c\right )^{2} + 288 \, {\left (a \cos \left (d x + c\right )^{2} - a\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) \sin \left (d x + c\right ) + 3 \, {\left (8 \, a \cos \left (d x + c\right )^{6} + 24 \, a \cos \left (d x + c\right )^{4} - 51 \, a \cos \left (d x + c\right )^{2} + 3 \, a\right )} \sin \left (d x + c\right ) + 512 \, a}{96 \, {\left (d \cos \left (d x + c\right )^{2} - d\right )} \sin \left (d x + c\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^4*(a+a*sin(d*x+c)),x, algorithm="fricas")

[Out]

-1/96*(32*a*cos(d*x + c)^6 + 192*a*cos(d*x + c)^4 - 768*a*cos(d*x + c)^2 + 288*(a*cos(d*x + c)^2 - a)*log(1/2*
sin(d*x + c))*sin(d*x + c) + 3*(8*a*cos(d*x + c)^6 + 24*a*cos(d*x + c)^4 - 51*a*cos(d*x + c)^2 + 3*a)*sin(d*x
+ c) + 512*a)/((d*cos(d*x + c)^2 - d)*sin(d*x + c))

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giac [A]  time = 0.22, size = 104, normalized size = 0.88 \[ -\frac {3 \, a \sin \left (d x + c\right )^{4} + 4 \, a \sin \left (d x + c\right )^{3} - 18 \, a \sin \left (d x + c\right )^{2} + 36 \, a \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) - 36 \, a \sin \left (d x + c\right ) - \frac {2 \, {\left (33 \, a \sin \left (d x + c\right )^{3} + 18 \, a \sin \left (d x + c\right )^{2} - 3 \, a \sin \left (d x + c\right ) - 2 \, a\right )}}{\sin \left (d x + c\right )^{3}}}{12 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^4*(a+a*sin(d*x+c)),x, algorithm="giac")

[Out]

-1/12*(3*a*sin(d*x + c)^4 + 4*a*sin(d*x + c)^3 - 18*a*sin(d*x + c)^2 + 36*a*log(abs(sin(d*x + c))) - 36*a*sin(
d*x + c) - 2*(33*a*sin(d*x + c)^3 + 18*a*sin(d*x + c)^2 - 3*a*sin(d*x + c) - 2*a)/sin(d*x + c)^3)/d

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maple [A]  time = 0.31, size = 195, normalized size = 1.65 \[ -\frac {a \left (\cos ^{8}\left (d x +c \right )\right )}{2 d \sin \left (d x +c \right )^{2}}-\frac {a \left (\cos ^{6}\left (d x +c \right )\right )}{2 d}-\frac {3 a \left (\cos ^{4}\left (d x +c \right )\right )}{4 d}-\frac {3 a \left (\cos ^{2}\left (d x +c \right )\right )}{2 d}-\frac {3 a \ln \left (\sin \left (d x +c \right )\right )}{d}-\frac {a \left (\cos ^{8}\left (d x +c \right )\right )}{3 d \sin \left (d x +c \right )^{3}}+\frac {5 a \left (\cos ^{8}\left (d x +c \right )\right )}{3 d \sin \left (d x +c \right )}+\frac {16 a \sin \left (d x +c \right )}{3 d}+\frac {5 \left (\cos ^{6}\left (d x +c \right )\right ) \sin \left (d x +c \right ) a}{3 d}+\frac {2 a \sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )}{d}+\frac {8 \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right ) a}{3 d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^7*csc(d*x+c)^4*(a+a*sin(d*x+c)),x)

[Out]

-1/2/d*a/sin(d*x+c)^2*cos(d*x+c)^8-1/2*a*cos(d*x+c)^6/d-3/4*a*cos(d*x+c)^4/d-3/2*a*cos(d*x+c)^2/d-3*a*ln(sin(d
*x+c))/d-1/3/d*a/sin(d*x+c)^3*cos(d*x+c)^8+5/3/d*a/sin(d*x+c)*cos(d*x+c)^8+16/3*a*sin(d*x+c)/d+5/3/d*cos(d*x+c
)^6*sin(d*x+c)*a+2/d*a*sin(d*x+c)*cos(d*x+c)^4+8/3/d*a*sin(d*x+c)*cos(d*x+c)^2

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maxima [A]  time = 0.33, size = 92, normalized size = 0.78 \[ -\frac {3 \, a \sin \left (d x + c\right )^{4} + 4 \, a \sin \left (d x + c\right )^{3} - 18 \, a \sin \left (d x + c\right )^{2} + 36 \, a \log \left (\sin \left (d x + c\right )\right ) - 36 \, a \sin \left (d x + c\right ) - \frac {2 \, {\left (18 \, a \sin \left (d x + c\right )^{2} - 3 \, a \sin \left (d x + c\right ) - 2 \, a\right )}}{\sin \left (d x + c\right )^{3}}}{12 \, d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^4*(a+a*sin(d*x+c)),x, algorithm="maxima")

[Out]

-1/12*(3*a*sin(d*x + c)^4 + 4*a*sin(d*x + c)^3 - 18*a*sin(d*x + c)^2 + 36*a*log(sin(d*x + c)) - 36*a*sin(d*x +
c) - 2*(18*a*sin(d*x + c)^2 - 3*a*sin(d*x + c) - 2*a)/sin(d*x + c)^3)/d

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mupad [B]  time = 9.07, size = 300, normalized size = 2.54 \[ \frac {11\,a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{8\,d}+\frac {3\,a\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{d}-\frac {a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{8\,d}-\frac {a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{24\,d}-\frac {3\,a\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d}+\frac {59\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+47\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\frac {499\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8}{3}+60\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\frac {562\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{3}+42\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+90\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-4\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\frac {29\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{3}-a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-\frac {a}{3}}{d\,\left (8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+48\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+8\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cos(c + d*x)^7*(a + a*sin(c + d*x)))/sin(c + d*x)^4,x)

[Out]

(11*a*tan(c/2 + (d*x)/2))/(8*d) + (3*a*log(tan(c/2 + (d*x)/2)^2 + 1))/d - (a*tan(c/2 + (d*x)/2)^2)/(8*d) - (a*
tan(c/2 + (d*x)/2)^3)/(24*d) - (3*a*log(tan(c/2 + (d*x)/2)))/d + ((29*a*tan(c/2 + (d*x)/2)^2)/3 - a*tan(c/2 +
(d*x)/2) - a/3 - 4*a*tan(c/2 + (d*x)/2)^3 + 90*a*tan(c/2 + (d*x)/2)^4 + 42*a*tan(c/2 + (d*x)/2)^5 + (562*a*tan
(c/2 + (d*x)/2)^6)/3 + 60*a*tan(c/2 + (d*x)/2)^7 + (499*a*tan(c/2 + (d*x)/2)^8)/3 + 47*a*tan(c/2 + (d*x)/2)^9
+ 59*a*tan(c/2 + (d*x)/2)^10)/(d*(8*tan(c/2 + (d*x)/2)^3 + 32*tan(c/2 + (d*x)/2)^5 + 48*tan(c/2 + (d*x)/2)^7 +
32*tan(c/2 + (d*x)/2)^9 + 8*tan(c/2 + (d*x)/2)^11))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**7*csc(d*x+c)**4*(a+a*sin(d*x+c)),x)

[Out]

Timed out

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